Optimal. Leaf size=94 \[ \frac {407}{800} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {37}{80} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{10} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {4477 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{800 \sqrt {10}} \]
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Rubi [A]
time = 0.02, antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {81, 52, 56, 222}
\begin {gather*} \frac {4477 \text {ArcSin}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{800 \sqrt {10}}-\frac {1}{10} (5 x+3)^{3/2} (1-2 x)^{3/2}-\frac {37}{80} \sqrt {5 x+3} (1-2 x)^{3/2}+\frac {407}{800} \sqrt {5 x+3} \sqrt {1-2 x} \end {gather*}
Antiderivative was successfully verified.
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Rule 52
Rule 56
Rule 81
Rule 222
Rubi steps
\begin {align*} \int \sqrt {1-2 x} (2+3 x) \sqrt {3+5 x} \, dx &=-\frac {1}{10} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {37}{20} \int \sqrt {1-2 x} \sqrt {3+5 x} \, dx\\ &=-\frac {37}{80} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{10} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {407}{160} \int \frac {\sqrt {1-2 x}}{\sqrt {3+5 x}} \, dx\\ &=\frac {407}{800} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {37}{80} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{10} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {4477 \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx}{1600}\\ &=\frac {407}{800} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {37}{80} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{10} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {4477 \text {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{800 \sqrt {5}}\\ &=\frac {407}{800} \sqrt {1-2 x} \sqrt {3+5 x}-\frac {37}{80} (1-2 x)^{3/2} \sqrt {3+5 x}-\frac {1}{10} (1-2 x)^{3/2} (3+5 x)^{3/2}+\frac {4477 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{800 \sqrt {10}}\\ \end {align*}
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Mathematica [A]
time = 0.14, size = 73, normalized size = 0.78 \begin {gather*} \frac {10 \sqrt {1-2 x} \left (-609+1445 x+6500 x^2+4000 x^3\right )-4477 \sqrt {30+50 x} \tan ^{-1}\left (\frac {\sqrt {\frac {5}{2}-5 x}}{\sqrt {3+5 x}}\right )}{8000 \sqrt {3+5 x}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.33, size = 87, normalized size = 0.93
method | result | size |
default | \(\frac {\sqrt {1-2 x}\, \sqrt {3+5 x}\, \left (16000 x^{2} \sqrt {-10 x^{2}-x +3}+4477 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )+16400 x \sqrt {-10 x^{2}-x +3}-4060 \sqrt {-10 x^{2}-x +3}\right )}{16000 \sqrt {-10 x^{2}-x +3}}\) | \(87\) |
risch | \(-\frac {\left (800 x^{2}+820 x -203\right ) \sqrt {3+5 x}\, \left (-1+2 x \right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{800 \sqrt {-\left (3+5 x \right ) \left (-1+2 x \right )}\, \sqrt {1-2 x}}+\frac {4477 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right ) \sqrt {\left (1-2 x \right ) \left (3+5 x \right )}}{16000 \sqrt {1-2 x}\, \sqrt {3+5 x}}\) | \(98\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.50, size = 55, normalized size = 0.59 \begin {gather*} -\frac {1}{10} \, {\left (-10 \, x^{2} - x + 3\right )}^{\frac {3}{2}} + \frac {37}{40} \, \sqrt {-10 \, x^{2} - x + 3} x - \frac {4477}{16000} \, \sqrt {10} \arcsin \left (-\frac {20}{11} \, x - \frac {1}{11}\right ) + \frac {37}{800} \, \sqrt {-10 \, x^{2} - x + 3} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.98, size = 67, normalized size = 0.71 \begin {gather*} \frac {1}{800} \, {\left (800 \, x^{2} + 820 \, x - 203\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1} - \frac {4477}{16000} \, \sqrt {10} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 68.92, size = 209, normalized size = 2.22 \begin {gather*} - \frac {7 \sqrt {2} \left (\begin {cases} \frac {121 \sqrt {5} \left (- \frac {\sqrt {5} \sqrt {1 - 2 x} \sqrt {10 x + 6} \cdot \left (20 x + 1\right )}{121} + \operatorname {asin}{\left (\frac {\sqrt {55} \sqrt {1 - 2 x}}{11} \right )}\right )}{200} & \text {for}\: \sqrt {1 - 2 x} > - \frac {\sqrt {55}}{5} \wedge \sqrt {1 - 2 x} < \frac {\sqrt {55}}{5} \end {cases}\right )}{4} + \frac {3 \sqrt {2} \left (\begin {cases} \frac {1331 \sqrt {5} \left (- \frac {5 \sqrt {5} \left (1 - 2 x\right )^{\frac {3}{2}} \left (10 x + 6\right )^{\frac {3}{2}}}{7986} - \frac {\sqrt {5} \sqrt {1 - 2 x} \sqrt {10 x + 6} \cdot \left (20 x + 1\right )}{1936} + \frac {\operatorname {asin}{\left (\frac {\sqrt {55} \sqrt {1 - 2 x}}{11} \right )}}{16}\right )}{125} & \text {for}\: \sqrt {1 - 2 x} > - \frac {\sqrt {55}}{5} \wedge \sqrt {1 - 2 x} < \frac {\sqrt {55}}{5} \end {cases}\right )}{4} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 140 vs.
\(2 (67) = 134\).
time = 0.57, size = 140, normalized size = 1.49 \begin {gather*} \frac {1}{8000} \, \sqrt {5} {\left (2 \, {\left (4 \, {\left (40 \, x - 59\right )} {\left (5 \, x + 3\right )} + 1293\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} + 4785 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {19}{2000} \, \sqrt {5} {\left (2 \, {\left (20 \, x - 23\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5} - 143 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right )\right )} + \frac {3}{25} \, \sqrt {5} {\left (11 \, \sqrt {2} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + 2 \, \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 7.48, size = 588, normalized size = 6.26 \begin {gather*} 2\,\sqrt {1-2\,x}\,\sqrt {5\,x+3}\,\left (\frac {x}{2}+\frac {1}{40}\right )-\frac {363\,\sqrt {10}\,\mathrm {atan}\left (\frac {\sqrt {10}\,\left (\sqrt {1-2\,x}-1\right )}{2\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}\right )}{4000}-\frac {\frac {7543\,{\left (\sqrt {1-2\,x}-1\right )}^3}{78125\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^3}-\frac {726\,\left (\sqrt {1-2\,x}-1\right )}{390625\,\left (\sqrt {3}-\sqrt {5\,x+3}\right )}-\frac {19023\,{\left (\sqrt {1-2\,x}-1\right )}^5}{15625\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^5}+\frac {19023\,{\left (\sqrt {1-2\,x}-1\right )}^7}{6250\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^7}-\frac {7543\,{\left (\sqrt {1-2\,x}-1\right )}^9}{5000\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^9}+\frac {363\,{\left (\sqrt {1-2\,x}-1\right )}^{11}}{2000\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^{11}}+\frac {1152\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^2}{15625\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}-\frac {11136\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^4}{15625\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^4}+\frac {15936\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^6}{3125\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^6}-\frac {2784\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^8}{625\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^8}+\frac {72\,\sqrt {3}\,{\left (\sqrt {1-2\,x}-1\right )}^{10}}{25\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^{10}}}{\frac {192\,{\left (\sqrt {1-2\,x}-1\right )}^2}{3125\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^2}+\frac {48\,{\left (\sqrt {1-2\,x}-1\right )}^4}{125\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^4}+\frac {32\,{\left (\sqrt {1-2\,x}-1\right )}^6}{25\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^6}+\frac {12\,{\left (\sqrt {1-2\,x}-1\right )}^8}{5\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^8}+\frac {12\,{\left (\sqrt {1-2\,x}-1\right )}^{10}}{5\,{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^{10}}+\frac {{\left (\sqrt {1-2\,x}-1\right )}^{12}}{{\left (\sqrt {3}-\sqrt {5\,x+3}\right )}^{12}}+\frac {64}{15625}}-\frac {\sqrt {2}\,\sqrt {5}\,\ln \left (x+\frac {1}{20}-\frac {\sqrt {10}\,\sqrt {1-2\,x}\,\sqrt {5\,x+3}\,1{}\mathrm {i}}{10}\right )\,121{}\mathrm {i}}{400} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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